Solve {l}{(-4)*[(-6)-(-8)]-(+3)*[(-11)+(+7)]}{[(+5)-(+2)]:[(-8)+(-3)-(-10)]}

$$\left. \begin{array} { l } { ( - 4 ) \cdot [ ( - 6 ) - ( - 8 ) ] - ( + 3 ) \cdot [ ( - 11 ) + ( + 7 ) ] } \\ { [ ( + 5 ) - ( + 2 ) ] : [ ( - 8 ) + ( - 3 ) - ( - 10 ) ] } \end{array} \right.$$

Sort

$$-3,4$$

Solution Steps

The opposite of -8 is 8.

$$sort(-4\left(-6+8\right)-3\left(-11+7\right),\frac{5-2}{-8-3-\left(-10\right)})$$

Add -6 and 8 to get 2.

$$sort(-4\times 2-3\left(-11+7\right),\frac{5-2}{-8-3-\left(-10\right)})$$

Multiply -4 and 2 to get -8.

$$sort(-8-3\left(-11+7\right),\frac{5-2}{-8-3-\left(-10\right)})$$

Add -11 and 7 to get -4.

$$sort(-8-3\left(-4\right),\frac{5-2}{-8-3-\left(-10\right)})$$

Multiply 3 and -4 to get -12.

$$sort(-8-\left(-12\right),\frac{5-2}{-8-3-\left(-10\right)})$$

The opposite of -12 is 12.

$$sort(-8+12,\frac{5-2}{-8-3-\left(-10\right)})$$

Add -8 and 12 to get 4.

$$sort(4,\frac{5-2}{-8-3-\left(-10\right)})$$

Subtract 2 from 5 to get 3.

$$sort(4,\frac{3}{-8-3-\left(-10\right)})$$

Subtract 3 from -8 to get -11.

$$sort(4,\frac{3}{-11-\left(-10\right)})$$

The opposite of -10 is 10.

$$sort(4,\frac{3}{-11+10})$$

Add -11 and 10 to get -1.

$$sort(4,\frac{3}{-1})$$

Fraction \frac{3}{-1} can be rewritten as -3 by extracting the negative sign.

$$sort(4,-3)$$

To sort the list, start from a single element 4.

$$4$$

Insert -3 to the appropriate location in the new list.

$$-3,4$$

Evaluate

$$4,\ -3$$