Solve {l}{(-3)^{4}+(-2)^{6}}{10^3+(-10)^3+10^2+(-10)^2}

$$\left. \begin{array} { l } { ( - 3 ) ^ { 4 } + ( - 2 ) ^ { 6 } } \\ { 10 ^ { 3 } + ( - 10 ) ^ { 3 } + 10 ^ { 2 } + ( - 10 ) ^ { 2 } } \end{array} \right.$$

Sort

$$145,\ 200$$

Solution Steps

Calculate -3 to the power of 4 and get 81.

$$sort(81+\left(-2\right)^{6},10^{3}+\left(-10\right)^{3}+10^{2}+\left(-10\right)^{2})$$

Calculate -2 to the power of 6 and get 64.

$$sort(81+64,10^{3}+\left(-10\right)^{3}+10^{2}+\left(-10\right)^{2})$$

Add 81 and 64 to get 145.

$$sort(145,10^{3}+\left(-10\right)^{3}+10^{2}+\left(-10\right)^{2})$$

Calculate 10 to the power of 3 and get 1000.

$$sort(145,1000+\left(-10\right)^{3}+10^{2}+\left(-10\right)^{2})$$

Calculate -10 to the power of 3 and get -1000.

$$sort(145,1000-1000+10^{2}+\left(-10\right)^{2})$$

Subtract 1000 from 1000 to get 0.

$$sort(145,10^{2}+\left(-10\right)^{2})$$

Calculate 10 to the power of 2 and get 100.

$$sort(145,100+\left(-10\right)^{2})$$

Calculate -10 to the power of 2 and get 100.

$$sort(145,100+100)$$

Add 100 and 100 to get 200.

$$sort(145,200)$$

The list values are already in order.

$$145,200$$

Evaluate

$$145,\ 200$$