Solve {l}{(-3)+(-1)+(+4)+(+2)=-6}{(+6)+(-5)+(+3)+(-2)=12}

$$\left. \begin{array} { l } { ( - 3 ) + ( - 1 ) + ( + 4 ) + ( + 2 ) = - 6 } \\ { ( + 6 ) + ( - 5 ) + ( + 3 ) + ( - 2 ) = 12 } \end{array} \right.$$

Verify

Solution Steps

Subtract 1 from -3 to get -4.

$$-4+4+2=-6\text{ and }6-5+3-2=12$$

Add -4 and 4 to get 0.

$$2=-6\text{ and }6-5+3-2=12$$

Compare 2 and -6.

$$\text{false}\text{ and }6-5+3-2=12$$

Subtract 5 from 6 to get 1.

$$\text{false}\text{ and }1+3-2=12$$

Add 1 and 3 to get 4.

$$\text{false}\text{ and }4-2=12$$

Subtract 2 from 4 to get 2.

$$\text{false}\text{ and }2=12$$

Compare 2 and 12.

$$\text{false}\text{ and }\text{false}$$

The conjunction of \text{false} and \text{false} is \text{false}.

$$\text{false}$$