Solve {l}{(-2)^3+(-3)^2-(-1)^2-(-2)^5}{-8+9-1-(+38)}

$$\left. \begin{array} { l } { ( - 2 ) ^ { 3 } + ( - 3 ) ^ { 2 } - ( - 1 ) ^ { 2 } - ( - 2 ) ^ { 5 } } \\ { - 8 + 9 - 1 - ( + 38 ) } \end{array} \right.$$

Evaluate

$$-6$$

Solution Steps

Calculate -2 to the power of 3 and get -8.

$$-8+\left(-3\right)^{2}-\left(-1\right)^{2}-\left(-2\right)^{5}-8+9-1-38$$

Calculate -3 to the power of 2 and get 9.

$$-8+9-\left(-1\right)^{2}-\left(-2\right)^{5}-8+9-1-38$$

Add -8 and 9 to get 1.

$$1-\left(-1\right)^{2}-\left(-2\right)^{5}-8+9-1-38$$

Calculate -1 to the power of 2 and get 1.

$$1-1-\left(-2\right)^{5}-8+9-1-38$$

Subtract 1 from 1 to get 0.

$$0-\left(-2\right)^{5}-8+9-1-38$$

Calculate -2 to the power of 5 and get -32.

$$0-\left(-32\right)-8+9-1-38$$

The opposite of -32 is 32.

$$0+32-8+9-1-38$$

Add 0 and 32 to get 32.

$$32-8+9-1-38$$

Subtract 8 from 32 to get 24.

$$24+9-1-38$$

Add 24 and 9 to get 33.

$$33-1-38$$

Subtract 1 from 33 to get 32.

$$32-38$$

Subtract 38 from 32 to get -6.

$$-6$$

Factor

$$-6$$