Solve {l}{(7/10-1/5)*-2/7}{142/35}

$$\left. \begin{array} { l } { ( \frac { 7 } { 10 } - \frac { 1 } { 5 } ) \cdot \frac { - 2 } { 7 } } \\ { 142 / 35 } \end{array} \right.$$

Sort

$$-\frac{1}{7},\ \frac{142}{35}$$

Solution Steps

Least common multiple of 10 and 5 is 10. Convert \frac{7}{10} and \frac{1}{5} to fractions with denominator 10.

$$sort(\left(\frac{7}{10}-\frac{2}{10}\right)\times \frac{-2}{7},\frac{142}{35})$$

Since \frac{7}{10} and \frac{2}{10} have the same denominator, subtract them by subtracting their numerators.

$$sort(\frac{7-2}{10}\times \frac{-2}{7},\frac{142}{35})$$

Subtract 2 from 7 to get 5.

$$sort(\frac{5}{10}\times \frac{-2}{7},\frac{142}{35})$$

Reduce the fraction \frac{5}{10} to lowest terms by extracting and canceling out 5.

$$sort(\frac{1}{2}\times \frac{-2}{7},\frac{142}{35})$$

Fraction \frac{-2}{7} can be rewritten as -\frac{2}{7} by extracting the negative sign.

$$sort(\frac{1}{2}\left(-\frac{2}{7}\right),\frac{142}{35})$$

Multiply \frac{1}{2} times -\frac{2}{7} by multiplying numerator times numerator and denominator times denominator.

$$sort(\frac{1\left(-2\right)}{2\times 7},\frac{142}{35})$$

Do the multiplications in the fraction \frac{1\left(-2\right)}{2\times 7}.

$$sort(\frac{-2}{14},\frac{142}{35})$$

Reduce the fraction \frac{-2}{14} to lowest terms by extracting and canceling out 2.

$$sort(-\frac{1}{7},\frac{142}{35})$$

Least common denominator of the numbers in the list -\frac{1}{7},\frac{142}{35} is 35. Convert numbers in the list to fractions with denominator 35.

$$-\frac{5}{35},\frac{142}{35}$$

Evaluate

$$-\frac{1}{7},\ \frac{142}{35}$$