Solve {l}{(1/8)^-2:(-4)-(5^0)^3}{8^2:(-4)-1}

$$\left. \begin{array} { l } { ( \frac { 1 } { 8 } ) ^ { - 2 } : ( - 4 ) - ( 5 ^ { 0 } ) ^ { 3 } } \\ { 8 ^ { 2 } : ( - 4 ) - 1 } \end{array} \right.$$

Sort

$$-17,\ -17$$

Solution Steps

To raise a power to another power, multiply the exponents. Multiply 0 and 3 to get 0.

$$sort(\frac{\left(\frac{1}{8}\right)^{-2}}{-4}-5^{0},\frac{8^{2}}{-4}-1)$$

Calculate \frac{1}{8} to the power of -2 and get 64.

$$sort(\frac{64}{-4}-5^{0},\frac{8^{2}}{-4}-1)$$

Divide 64 by -4 to get -16.

$$sort(-16-5^{0},\frac{8^{2}}{-4}-1)$$

Calculate 5 to the power of 0 and get 1.

$$sort(-16-1,\frac{8^{2}}{-4}-1)$$

Subtract 1 from -16 to get -17.

$$sort(-17,\frac{8^{2}}{-4}-1)$$

Calculate 8 to the power of 2 and get 64.

$$sort(-17,\frac{64}{-4}-1)$$

Divide 64 by -4 to get -16.

$$sort(-17,-16-1)$$

Subtract 1 from -16 to get -17.

$$sort(-17,-17)$$

The list values are already in order.

$$-17,-17$$

Evaluate

$$-17,\ -17$$