\left. \begin{array} { l } { \text { hy-x } = 8 } \\ { 7 h + 8 x = 63 } \end{array} \right.
Solve for x, y
x=\frac{63-7h}{8}
y=-\frac{7}{8}+\frac{127}{8h}
h\neq 0
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8x+7h=63,-x+hy=8
To solve a pair of equations using substitution, first solve one of the equations for one of the variables. Then substitute the result for that variable in the other equation.
8x+7h=63
Pick one of the two equations which is more simple to solve for x by isolating x on the left hand side of the equal sign.
8x=63-7h
Subtract 7h from both sides of the equation.
x=\frac{63-7h}{8}
Divide both sides by 8.
-\frac{63-7h}{8}+hy=8
Substitute \frac{63-7h}{8} for x in the other equation, -x+hy=8.
hy=\frac{127-7h}{8}
Subtract \frac{-63+7h}{8} from both sides of the equation.
y=-\frac{7}{8}+\frac{127}{8h}
Divide both sides by h.
x=\frac{63-7h}{8},y=-\frac{7}{8}+\frac{127}{8h}
The system is now solved.
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