Solve {l}{text{If}p(x)=x+3text{,then}p(x)+p(-x)text{isequal}}{{llll}{text{a)}0}&{text{b)}6}&{text{c)}2x}&{text{d)}3}}

$$\left. \begin{array} { l } { \text { If } p ( x ) = x + 3 \text { , then } p ( x ) + p ( - x ) \text { is equal } } \\ { \left. \begin{array} { l l l l } { \text { a) } 0 } & { \text { b) } 6 } & { \text { c) } 2 x } & { \text { d) } 3 } \end{array} \right. } \end{array} \right.$$

Solve for x

$$x=\frac{3}{p-1}$$

$$p\neq 1$$

Steps for Solving Linear Equation

Subtract x from both sides.

$$px-x=3$$

Combine all terms containing x.

$$\left(p-1\right)x=3$$

Divide both sides by p-1.

$$\frac{\left(p-1\right)x}{p-1}=\frac{3}{p-1}$$

Dividing by p-1 undoes the multiplication by p-1.

$$x=\frac{3}{p-1}$$