Solve {l}{text{Findanequationforthelineperpendicularto}4x+32y=96}{(-10,-4)text{.}}{text{Writeyouranswerintheform}y=mx+btext{.}}

$$\left. \begin{array} { l } { \text { Find an equation for the line perpendicular to } 4 x + 32 y = 96 } \\ { ( - 10 , - 4 ) \text { . } } \\ { \text { Write your answer in the form } y = m x + b \text { . } } \end{array} \right.$$

Solve for x (complex solution)

$$\left\{\begin{matrix}x=-\frac{b-y}{m}\text{, }&m\neq 0\\x\in \mathrm{C}\text{, }&y=b\text{ and }m=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Swap sides so that all variable terms are on the left hand side.

$$mx+b=y$$

Subtract b from both sides.

$$mx=y-b$$

Divide both sides by m.

$$\frac{mx}{m}=\frac{y-b}{m}$$

Dividing by m undoes the multiplication by m.

$$x=\frac{y-b}{m}$$

Solve for x

$$\left\{\begin{matrix}x=-\frac{b-y}{m}\text{, }&m\neq 0\\x\in \mathrm{R}\text{, }&y=b\text{ and }m=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Swap sides so that all variable terms are on the left hand side.

$$mx+b=y$$

Subtract b from both sides.

$$mx=y-b$$

Divide both sides by m.

$$\frac{mx}{m}=\frac{y-b}{m}$$

Dividing by m undoes the multiplication by m.

$$x=\frac{y-b}{m}$$