Solve {l}{text{(2)}2m+7=9}{text{(5)}9x/8+1=10}{text{(8)}3(y+8)=10(y-4)+}{text{(b+}1)+(b+2)=21}

$$\left. \begin{array} { l } { \text { (2) } 2 m + 7 = 9 } \\ { \text { (5) } \frac { 9 x } { 8 } + 1 = 10 } \\ { \text { (8) } 3 ( y + 8 ) = 10 ( y - 4 ) + } \\ { \text { (b+ } 1 ) + ( b + 2 ) = 21 } \end{array} \right.$$

Solve for m, x

$$x=8$$

$$m=1$$

Solution Steps

Consider the first equation. Subtract 7 from both sides.

$$2m=9-7$$

Subtract 7 from 9 to get 2.

$$2m=2$$

Divide both sides by 2.

$$m=\frac{2}{2}$$

Divide 2 by 2 to get 1.

$$m=1$$

Consider the second equation. Multiply both sides of the equation by 8.

$$9x+8=80$$

Subtract 8 from both sides.

$$9x=80-8$$

Subtract 8 from 80 to get 72.

$$9x=72$$

Divide both sides by 9.

$$x=\frac{72}{9}$$

Divide 72 by 9 to get 8.

$$x=8$$

The system is now solved.

$$m=1 x=8$$