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2\sqrt{2}-7+4,3
Factor 8=2^{2}\times 2. Rewrite the square root of the product \sqrt{2^{2}\times 2} as the product of square roots \sqrt{2^{2}}\sqrt{2}. Take the square root of 2^{2}.
2\sqrt{2}-2,7
Add -7 and 4,3 to get -2,7.