Solve for x (complex solution)
x=\sqrt{y}-5\sqrt{2}
Solve for x
x=\sqrt{y}-5\sqrt{2}
y\geq 0
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\sqrt{2}x+10=\sqrt{2y}
Add \sqrt{2y} to both sides. Anything plus zero gives itself.
\sqrt{2}x=\sqrt{2y}-10
Subtract 10 from both sides.
\frac{\sqrt{2}x}{\sqrt{2}}=\frac{\sqrt{2y}-10}{\sqrt{2}}
Divide both sides by \sqrt{2}.
x=\frac{\sqrt{2y}-10}{\sqrt{2}}
Dividing by \sqrt{2} undoes the multiplication by \sqrt{2}.
x=\sqrt{y}-5\sqrt{2}
Divide \sqrt{2y}-10 by \sqrt{2}.
\sqrt{2}x+10=\sqrt{2y}
Add \sqrt{2y} to both sides. Anything plus zero gives itself.
\sqrt{2}x=\sqrt{2y}-10
Subtract 10 from both sides.
\frac{\sqrt{2}x}{\sqrt{2}}=\frac{\sqrt{2y}-10}{\sqrt{2}}
Divide both sides by \sqrt{2}.
x=\frac{\sqrt{2y}-10}{\sqrt{2}}
Dividing by \sqrt{2} undoes the multiplication by \sqrt{2}.
x=\sqrt{y}-5\sqrt{2}
Divide \sqrt{2y}-10 by \sqrt{2}.
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