Solve {l}{sin60}{+20560}

$$\left. \begin{array} { l } { \sin 60 } \\ { + 20560 } \end{array} \right.$$

Evaluate

$$\frac{\sqrt{3}}{2}+20560\approx 20560.866025404$$

Short Solution Steps

Get the value of \sin(60) from trigonometric values table.

$$\frac{\sqrt{3}}{2}+20560$$

To add or subtract expressions, expand them to make their denominators the same. Multiply 20560 times \frac{2}{2}.

$$\frac{\sqrt{3}}{2}+\frac{20560\times 2}{2}$$

Since \frac{\sqrt{3}}{2} and \frac{20560\times 2}{2} have the same denominator, add them by adding their numerators.

$$\frac{\sqrt{3}+20560\times 2}{2}$$

Do the multiplications in \sqrt{3}+20560\times 2.

$$\frac{\sqrt{3}+41120}{2}$$