Solve {l}{log10^-2}{10^-2-5}

$$\left. \begin{array} { l } { \log 10 ^ { - 2 } } \\ { 10 ^ { - 2 } - 5 } \end{array} \right.$$

Sort

$$-\frac{499}{100},-2$$

Solution Steps

Calculate 10 to the power of -2 and get \frac{1}{100}.

$$sort(\log(\frac{1}{100}),10^{-2}-5)$$

The common logarithm of \frac{1}{100} is -2.

$$sort(-2,10^{-2}-5)$$

Calculate 10 to the power of -2 and get \frac{1}{100}.

$$sort(-2,\frac{1}{100}-5)$$

Subtract 5 from \frac{1}{100} to get -\frac{499}{100}.

$$sort(-2,-\frac{499}{100})$$

Convert decimal numbers in the list -2,-\frac{499}{100} to fractions.

$$-2,-\frac{499}{100}$$

To sort the list, start from a single element -2.

$$-2$$

Insert -\frac{499}{100} to the appropriate location in the new list.

$$-\frac{499}{100},-2$$

Evaluate

$$-2,\ -\frac{499}{100}$$