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Solve for λ, V, m, z
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12.14=\frac{2V\times 7.54}{1-2V}
Consider the first equation. Insert the known values of variables into the equation.
12.14\left(-2V+1\right)=2V\times 7.54
Variable V cannot be equal to \frac{1}{2} since division by zero is not defined. Multiply both sides of the equation by -2V+1.
-24.28V+12.14=2V\times 7.54
Use the distributive property to multiply 12.14 by -2V+1.
-24.28V+12.14=15.08V
Multiply 2 and 7.54 to get 15.08.
-24.28V+12.14-15.08V=0
Subtract 15.08V from both sides.
-39.36V+12.14=0
Combine -24.28V and -15.08V to get -39.36V.
-39.36V=-12.14
Subtract 12.14 from both sides. Anything subtracted from zero gives its negation.
V=\frac{-12.14}{-39.36}
Divide both sides by -39.36.
V=\frac{-1214}{-3936}
Expand \frac{-12.14}{-39.36} by multiplying both numerator and the denominator by 100.
V=\frac{607}{1968}
Reduce the fraction \frac{-1214}{-3936} to lowest terms by extracting and canceling out -2.
z=\frac{15.08}{16.84-12.14}
Consider the fourth equation. Multiply 2 and 7.54 to get 15.08.
z=\frac{15.08}{4.7}
Subtract 12.14 from 16.84 to get 4.7.
z=\frac{1508}{470}
Expand \frac{15.08}{4.7} by multiplying both numerator and the denominator by 100.
z=\frac{754}{235}
Reduce the fraction \frac{1508}{470} to lowest terms by extracting and canceling out 2.
\lambda =12.14 V=\frac{607}{1968} m=7.54 z=\frac{754}{235}
The system is now solved.