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\frac{-2-y}{3}-\frac{-2+y}{2}=1
Consider the first equation. Insert the known values of variables into the equation.
2\left(-2-y\right)-3\left(-2+y\right)=6
Multiply both sides of the equation by 6, the least common multiple of 3,2.
-4-2y-3\left(-2+y\right)=6
Use the distributive property to multiply 2 by -2-y.
-4-2y+6-3y=6
Use the distributive property to multiply -3 by -2+y.
2-2y-3y=6
Add -4 and 6 to get 2.
2-5y=6
Combine -2y and -3y to get -5y.
-5y=6-2
Subtract 2 from both sides.
-5y=4
Subtract 2 from 6 to get 4.
y=-\frac{4}{5}
Divide both sides by -5.
x=-2 y=-\frac{4}{5}
The system is now solved.