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Solve for x, y
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x-5=-\frac{2}{3}\times 2
Consider the second equation. Multiply both sides by 2.
x-5=-\frac{4}{3}
Multiply -\frac{2}{3} and 2 to get -\frac{4}{3}.
x=-\frac{4}{3}+5
Add 5 to both sides.
x=\frac{11}{3}
Add -\frac{4}{3} and 5 to get \frac{11}{3}.
\frac{\frac{11}{3}-1}{y-6}\left(-\frac{2}{3}\right)=-1
Consider the first equation. Insert the known values of variables into the equation.
\frac{\frac{11}{3}-1}{y-6}=-\left(-\frac{3}{2}\right)
Multiply both sides by -\frac{3}{2}, the reciprocal of -\frac{2}{3}.
\frac{\frac{11}{3}-1}{y-6}=\frac{3}{2}
Multiply -1 and -\frac{3}{2} to get \frac{3}{2}.
2\left(\frac{11}{3}-1\right)=3\left(y-6\right)
Variable y cannot be equal to 6 since division by zero is not defined. Multiply both sides of the equation by 2\left(y-6\right), the least common multiple of y-6,2.
2\times \frac{8}{3}=3\left(y-6\right)
Subtract 1 from \frac{11}{3} to get \frac{8}{3}.
\frac{16}{3}=3\left(y-6\right)
Multiply 2 and \frac{8}{3} to get \frac{16}{3}.
\frac{16}{3}=3y-18
Use the distributive property to multiply 3 by y-6.
3y-18=\frac{16}{3}
Swap sides so that all variable terms are on the left hand side.
3y=\frac{16}{3}+18
Add 18 to both sides.
3y=\frac{70}{3}
Add \frac{16}{3} and 18 to get \frac{70}{3}.
y=\frac{\frac{70}{3}}{3}
Divide both sides by 3.
y=\frac{70}{3\times 3}
Express \frac{\frac{70}{3}}{3} as a single fraction.
y=\frac{70}{9}
Multiply 3 and 3 to get 9.
x=\frac{11}{3} y=\frac{70}{9}
The system is now solved.