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120+120x\times \frac{2}{5}=5x
Consider the second equation. Variable x cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by 120x, the least common multiple of x,5,24.
120+48x=5x
Multiply 120 and \frac{2}{5} to get 48.
120+48x-5x=0
Subtract 5x from both sides.
120+43x=0
Combine 48x and -5x to get 43x.
43x=-120
Subtract 120 from both sides. Anything subtracted from zero gives its negation.
x=-\frac{120}{43}
Divide both sides by 43.
\frac{-\frac{120}{43}}{-\frac{120}{43}}+y=15
Consider the first equation. Insert the known values of variables into the equation.
1+y=15
Divide -\frac{120}{43} by -\frac{120}{43} to get 1.
y=15-1
Subtract 1 from both sides.
y=14
Subtract 1 from 15 to get 14.
x=-\frac{120}{43} y=14
The system is now solved.