Solve {l}{a+1/3}{a-3/3a}{5a^2/6a^2-18}{a+1/a^2-a}

\left. \begin{array} { l } { \frac { a + 1 } { 3 } } \\ { \frac { a - 3 } { 3 a } } \\ { \frac { 5 a ^ { 2 } } { 6 a ^ { 2 } - 18 } } \\ { \frac { a + 1 } { a ^ { 2 } - a } } \end{array} \right.

Evaluate

\frac{a+1}{3},\ \frac{a-3}{3a},\ \frac{5a^{2}}{6\left(a^{2}-3\right)},\ \frac{a+1}{a\left(a-1\right)}

Quiz

5 problems similar to:

\left. \begin{array} { l } { \frac { a + 1 } { 3 } } \\ { \frac { a - 3 } { 3 a } } \\ { \frac { 5 a ^ { 2 } } { 6 a ^ { 2 } - 18 } } \\ { \frac { a + 1 } { a ^ { 2 } - a } } \end{array} \right.

Similar Problems from Web Search

Can this integral be written in terms of hypergeometric function?

https://math.stackexchange.com/q/2474055

I think I figured out the anwer to this question. At least for |z|<1 we have a concrete definition of a generalized hypergeometric function: the ratio of consecutive coefficients should be a ...

Prove by induction that 4\sum_{k=-1}^{n}(5)^k = 5^{n+1}-\frac{1}{5}, \forall n \in \mathbb{N}

https://math.stackexchange.com/questions/2149314/prove-by-induction-that-4-sum-k-1n5k-5n1-frac15-forall-n

The problem is in the last line. We have \begin{array}{rcl}4\sum_{k=-1}^{h+1}(5)^k & = & 4\sum_{k=-1}^{h}(5)^k + 4\sum_{k=h+1}^{h+1}(5)^k \\ & = & 5^{h+1} -\frac{1}{5} + 4 \cdot 5^{h+1} \\ & = & 5 \cdot 5^{h+1} -\frac{1}{5} \\ & = & 5^{h+2} - \frac{1}{5}\end{array}

Show that the pseudoinverse of T is 1/4T.

https://math.stackexchange.com/questions/3115095/show-that-the-pseudoinverse-of-t-is-1-4t

The norm is irrelevant, as all norms on M_2(\mathbb{C}) are equivalent, being a finite dimensional vector space. The determinant of T^2+tI is (2+t)^2\color{red}{-4}=t^2+4t . So you need to ...

If a_n = \frac{{(n + 1)}^n}{n^{n - 1}} and c > 0 then \lim_{n \to \infty} n^{1-c}(a^c_n-a^c_{n-1}) =ce^c

https://math.stackexchange.com/questions/2259452/if-a-n-fracn-1nnn-1-and-c-0-then-lim-n-to-infty

I think the approach in my answer to the question which you have linked should work without much change. To simplify typing I will use A = a_{n}, B = a_{n - 1}. Note that A/n, B/n \to e. I first ...

Reformulation of optimization problem using kkt and lagrange conditions

https://math.stackexchange.com/questions/2863250/reformulation-of-optimization-problem-using-kkt-and-lagrange-conditions

Example: take \bar H=\begin{bmatrix}1 & 0\\0 & -2\end{bmatrix},\qquad \bar E=\begin{bmatrix}1 & -1\end{bmatrix}. Then you are minimizing y_1^2-2y_2^2 subject to y_1=y_2. The necessary ...

Taking 4 shots or 6?

https://math.stackexchange.com/questions/2888633/taking-4-shots-or-6/2888666

In the case of B(6,p) we fail with probability (0,1,2 shots) (1-p)^6+6p(1-p)^5+15p^2(1-p)^4. In the case of B(4,p) we fail with probability (0,1 shots) (1-p)^4+4p(1-p)^3. Now, we have ...

Copied to clipboard

Examples

Quadratic equation

{ x } ^ { 2 } - 4 x - 5 = 0

Trigonometry

4 \sin \theta \cos \theta = 2 \sin \theta

\left[ \begin{array} { l l } { 2 } & { 3 } \\ { 5 } & { 4 } \end{array} \right] \left[ \begin{array} { l l l } { 2 } & { 0 } & { 3 } \\ { -1 } & { 1 } & { 5 } \end{array} \right]

Simultaneous equation

\left. \begin{cases} { 8x+2y = 46 } \\ { 7x+3y = 47 } \end{cases} \right.

Differentiation

\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }

Integration

\int _ { 0 } ^ { 1 } x e ^ { - x ^ { 2 } } d x

Limits

\lim _{x \rightarrow-3} \frac{x^{2}-9}{x^{2}+2 x-3}

Topics

Topics

Similar Problems from Web Search

Share

Examples