Solve {l}{9/4+-7/3}{27+(-28)}{27-28}

$$\left. \begin{array} { l } { \frac { 9 } { 4 } + \frac { - 7 } { 3 } } \\ { 27 + ( - 28 ) } \\ { 27 - 28 } \end{array} \right.$$

Sort

$$-1,-1,-\frac{1}{12}$$

Solution Steps

Fraction \frac{-7}{3} can be rewritten as -\frac{7}{3} by extracting the negative sign.

$$sort(\frac{9}{4}-\frac{7}{3},27-28,27-28)$$

Least common multiple of 4 and 3 is 12. Convert \frac{9}{4} and \frac{7}{3} to fractions with denominator 12.

$$sort(\frac{27}{12}-\frac{28}{12},27-28,27-28)$$

Since \frac{27}{12} and \frac{28}{12} have the same denominator, subtract them by subtracting their numerators.

$$sort(\frac{27-28}{12},27-28,27-28)$$

Subtract 28 from 27 to get -1.

$$sort(-\frac{1}{12},27-28,27-28)$$

Subtract 28 from 27 to get -1.

$$sort(-\frac{1}{12},-1,27-28)$$

Subtract 28 from 27 to get -1.

$$sort(-\frac{1}{12},-1,-1)$$

Convert decimal numbers in the list -\frac{1}{12},-1,-1 to fractions.

$$-\frac{1}{12},-1,-1$$

To sort the list, start from a single element -\frac{1}{12}.

$$-\frac{1}{12}$$

Insert -1 to the appropriate location in the new list.

$$-1,-\frac{1}{12}$$

Insert -1 to the appropriate location in the new list.

$$-1,-1,-\frac{1}{12}$$

Evaluate

$$-\frac{1}{12},\ -1,\ -1$$