Solve {l}{740/3}{(15)}{803/4}{(16)}

$$\left. \begin{array} { l } { \frac { 740 } { 3 } } \\ { ( 15 ) } \\ { \frac { 803 } { 4 } } \\ { ( 16 ) } \end{array} \right.$$

Sort

$$15,16,\frac{803}{4},\frac{740}{3}$$

Solution Steps

Convert decimal numbers in the list \frac{740}{3},15,\frac{803}{4},16 to fractions.

$$\frac{740}{3},15,\frac{803}{4},16$$

Least common denominator of the numbers in the list \frac{740}{3},15,\frac{803}{4},16 is 12. Convert numbers in the list to fractions with denominator 12.

$$\frac{2960}{12},\frac{180}{12},\frac{2409}{12},\frac{192}{12}$$

To sort the list, start from a single element \frac{2960}{12}.

$$\frac{2960}{12}$$

Insert \frac{180}{12} to the appropriate location in the new list.

$$\frac{180}{12},\frac{2960}{12}$$

Insert \frac{2409}{12} to the appropriate location in the new list.

$$\frac{180}{12},\frac{2409}{12},\frac{2960}{12}$$

Insert \frac{192}{12} to the appropriate location in the new list.

$$\frac{180}{12},\frac{192}{12},\frac{2409}{12},\frac{2960}{12}$$

Replace the obtained fractions with the initial values.

$$15,16,\frac{803}{4},\frac{740}{3}$$

Evaluate

$$\frac{740}{3},\ 15,\ \frac{803}{4},\ 16$$