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6+y-10+5x=5x+5y-10
Consider the first equation. Multiply both sides of the equation by 5.
-4+y+5x=5x+5y-10
Subtract 10 from 6 to get -4.
-4+y+5x-5x=5y-10
Subtract 5x from both sides.
-4+y=5y-10
Combine 5x and -5x to get 0.
-4+y-5y=-10
Subtract 5y from both sides.
-4-4y=-10
Combine y and -5y to get -4y.
-4y=-10+4
Add 4 to both sides.
-4y=-6
Add -10 and 4 to get -6.
y=\frac{-6}{-4}
Divide both sides by -4.
y=\frac{3}{2}
Reduce the fraction \frac{-6}{-4} to lowest terms by extracting and canceling out -2.
\frac{3x+2}{4}+\frac{5\times \frac{3}{2}+8}{3}=5x+7\times \frac{3}{2}
Consider the second equation. Insert the known values of variables into the equation.
3\left(3x+2\right)+4\left(5\times \frac{3}{2}+8\right)=60x+84\times \frac{3}{2}
Multiply both sides of the equation by 12, the least common multiple of 4,3,2.
9x+6+4\left(5\times \frac{3}{2}+8\right)=60x+84\times \frac{3}{2}
Use the distributive property to multiply 3 by 3x+2.
9x+6+4\left(\frac{15}{2}+8\right)=60x+84\times \frac{3}{2}
Multiply 5 and \frac{3}{2} to get \frac{15}{2}.
9x+6+4\times \frac{31}{2}=60x+84\times \frac{3}{2}
Add \frac{15}{2} and 8 to get \frac{31}{2}.
9x+6+62=60x+84\times \frac{3}{2}
Multiply 4 and \frac{31}{2} to get 62.
9x+68=60x+84\times \frac{3}{2}
Add 6 and 62 to get 68.
9x+68=60x+126
Multiply 84 and \frac{3}{2} to get 126.
9x+68-60x=126
Subtract 60x from both sides.
-51x+68=126
Combine 9x and -60x to get -51x.
-51x=126-68
Subtract 68 from both sides.
-51x=58
Subtract 68 from 126 to get 58.
x=-\frac{58}{51}
Divide both sides by -51.
y=\frac{3}{2} x=-\frac{58}{51}
The system is now solved.