Solve for y, w, z
z=45
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2\times 480=6w
Consider the first equation. Variable y cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by 2y, the least common multiple of y,2y.
960=6w
Multiply 2 and 480 to get 960.
6w=960
Swap sides so that all variable terms are on the left hand side.
w=\frac{960}{6}
Divide both sides by 6.
w=160
Divide 960 by 6 to get 160.
w=160 z=45
The system is now solved.
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