Solve {l}{28/42}{25/10}{12/12}

$$\left. \begin{array} { l } { \frac { 28 } { 42 } } \\ { \frac { 25 } { 10 } } \\ { \frac { 12 } { 12 } } \end{array} \right.$$

Sort

$$\frac{2}{3},1,\frac{5}{2}$$

Solution Steps

Divide 12 by 12 to get 1.

$$sort(\frac{28}{42},\frac{25}{10},1)$$

Reduce the fraction \frac{28}{42} to lowest terms by extracting and canceling out 14.

$$sort(\frac{2}{3},\frac{25}{10},1)$$

Reduce the fraction \frac{25}{10} to lowest terms by extracting and canceling out 5.

$$sort(\frac{2}{3},\frac{5}{2},1)$$

Convert decimal numbers in the list \frac{2}{3},\frac{5}{2},1 to fractions.

$$\frac{2}{3},\frac{5}{2},1$$

Least common denominator of the numbers in the list \frac{2}{3},\frac{5}{2},1 is 6. Convert numbers in the list to fractions with denominator 6.

$$\frac{4}{6},\frac{15}{6},\frac{6}{6}$$

To sort the list, start from a single element \frac{4}{6}.

$$\frac{4}{6}$$

Insert \frac{15}{6} to the appropriate location in the new list.

$$\frac{4}{6},\frac{15}{6}$$

Insert \frac{6}{6} to the appropriate location in the new list.

$$\frac{4}{6},\frac{6}{6},\frac{15}{6}$$

Replace the obtained fractions with the initial values.

$$\frac{2}{3},1,\frac{5}{2}$$

Evaluate

$$\frac{2}{3},\ \frac{5}{2},\ 1$$