Solve for b, a
b=13
a=10
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26\times 20=b\times 40
Consider the first equation. Variable b cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by 26b, the least common multiple of b,26.
520=b\times 40
Multiply 26 and 20 to get 520.
b\times 40=520
Swap sides so that all variable terms are on the left hand side.
b=\frac{520}{40}
Divide both sides by 40.
b=13
Divide 520 by 40 to get 13.
2\times 35=7a
Consider the second equation. Variable a cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by 2a, the least common multiple of a,2.
70=7a
Multiply 2 and 35 to get 70.
7a=70
Swap sides so that all variable terms are on the left hand side.
a=\frac{70}{7}
Divide both sides by 7.
a=10
Divide 70 by 7 to get 10.
b=13 a=10
The system is now solved.
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