Solve for t, k
t=1.21
k=1.8
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11\times 11=100t
Consider the first equation. Variable t cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by 11t, the least common multiple of t,11.
121=100t
Multiply 11 and 11 to get 121.
100t=121
Swap sides so that all variable terms are on the left hand side.
t=\frac{121}{100}
Divide both sides by 100.
\frac{3}{7}\times 4.2=k
Consider the second equation. Multiply both sides by 4.2.
\frac{9}{5}=k
Multiply \frac{3}{7} and 4.2 to get \frac{9}{5}.
k=\frac{9}{5}
Swap sides so that all variable terms are on the left hand side.
t=\frac{121}{100} k=\frac{9}{5}
The system is now solved.
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