Solve {l}{-6+12/2400}{(400-6)+1200}

$$\left. \begin{array} { l } { \frac { - 6 + 12 } { 2400 } } \\ { ( 400 - 6 ) + 1200 } \end{array} \right.$$

Sort

$$\frac{1}{400},\ 1594$$

Solution Steps

Add -6 and 12 to get 6.

$$sort(\frac{6}{2400},400-6+1200)$$

Reduce the fraction \frac{6}{2400} to lowest terms by extracting and canceling out 6.

$$sort(\frac{1}{400},400-6+1200)$$

Subtract 6 from 400 to get 394.

$$sort(\frac{1}{400},394+1200)$$

Add 394 and 1200 to get 1594.

$$sort(\frac{1}{400},1594)$$

Convert decimal numbers in the list \frac{1}{400},1594 to fractions.

$$\frac{1}{400},1594$$

Evaluate

$$\frac{1}{400},\ 1594$$