Solve {l}{alpha^2+b+3=1}{alphab+7=2}

Solve for α, b

\alpha =\frac{18^{\frac{2}{3}}\left(\sqrt[3]{\sqrt{2121}+45}+\sqrt[3]{45-\sqrt{2121}}\right)}{18}\approx 1.328268856

b = -\frac{\sqrt[3]{18} {({(\sqrt{2121} + 45)} ^ {\frac{2}{3}} + {(45 - \sqrt{2121})} ^ {\frac{2}{3}} + 2 \cdot 18 ^ {\frac{2}{3}} - 4 \sqrt[3]{12})}}{18} \approx -3.764298153

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\left. \begin{array} { l } { \alpha ^ { 2 } + b + 3 = 1 } \\ { \alpha b + 7 = 2 } \end{array} \right.

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