Solve {l}{[4^{2}+3*(11^{2}-9^{2})]-10^{2}}:{[7^{3}-2^{8}*(35-5^{2}-3^{2})-3*5^{2}]-17^{3}:17^{3}+6^{0}}}{-6^{2}*5-7*3^{2})]:39+2^{5}*1^{5}-12*2^2}*7-(3^2*2^2+2^2*5)}

$$\left. \begin{array} { l } { [ 4 ^ { 2 } + 3 \times ( 11 ^ { 2 } - 9 ^ { 2 } ) ] - 10 ^ { 2 } \} : \{ [ 7 ^ { 3 } - 2 ^ { 8 } \times ( 35 - 5 ^ { 2 } - 3 ^ { 2 } ) - 3 \times 5 ^ { 2 } ] - 17 ^ { 3 } : 17 ^ { 3 } + 6 ^ { 0 } \} } \\ { - 6 ^ { 2 } \times 5 - 7 \times 3 ^ { 2 } ) ] : 39 + 2 ^ { 5 } \times 1 ^ { 5 } - 12 \times 2 ^ { 2 } \} \times 7 - ( 3 ^ { 2 } \times 2 ^ { 2 } + 2 ^ { 2 } \times 5 ) } \end{array} \right.$$

Evaluate

$$36$$

Solution Steps

Calculate 4 to the power of 2 and get 16.

$$16+3\left(11^{2}-9^{2}\right)-10^{2}$$

Calculate 11 to the power of 2 and get 121.

$$16+3\left(121-9^{2}\right)-10^{2}$$

Calculate 9 to the power of 2 and get 81.

$$16+3\left(121-81\right)-10^{2}$$

Subtract 81 from 121 to get 40.

$$16+3\times 40-10^{2}$$

Multiply 3 and 40 to get 120.

$$16+120-10^{2}$$

Add 16 and 120 to get 136.

$$136-10^{2}$$

Calculate 10 to the power of 2 and get 100.

$$136-100$$

Subtract 100 from 136 to get 36.

$$36$$

Factor

$$2^{2}\times 3^{2}$$