Solve {l}{[12-sqrt[3]{-27}]}{+sqrt{36}+sqrt{16}}{-(4div1)}

$$\left. \begin{array} { l } { [ 12 - \sqrt[ 3 ] { - 27 } ] } \\ { + \sqrt { 36 } + \sqrt { 16 } } \\ { - ( 4 \div 1 ) } \end{array} \right.$$

Evaluate

$$21$$

Solution Steps

Calculate \sqrt[3]{-27} and get -3.

$$12-\left(-3\right)+\sqrt{36}+\sqrt{16}-\frac{4}{1}$$

The opposite of -3 is 3.

$$12+3+\sqrt{36}+\sqrt{16}-\frac{4}{1}$$

Add 12 and 3 to get 15.

$$15+\sqrt{36}+\sqrt{16}-\frac{4}{1}$$

Calculate the square root of 36 and get 6.

$$15+6+\sqrt{16}-\frac{4}{1}$$

Add 15 and 6 to get 21.

$$21+\sqrt{16}-\frac{4}{1}$$

Calculate the square root of 16 and get 4.

$$21+4-\frac{4}{1}$$

Add 21 and 4 to get 25.

$$25-\frac{4}{1}$$

Anything divided by one gives itself.

$$25-4$$

Subtract 4 from 25 to get 21.

$$21$$

Factor

$$3\times 7$$