Solve {l}{[(18+3*2)div8+5*3]div6=3}{37+[25-(11+19-4)]=36}

$$\left. \begin{array} { l } { [ ( 18 + 3 \cdot 2 ) \div 8 + 5 \cdot 3 ] \div 6 = 3 } \\ { 37 + [ 25 - ( 11 + 19 - 4 ) ] = 36 } \end{array} \right.$$

Verify

Solution Steps

Multiply 3 and 2 to get 6.

$$\frac{\frac{18+6}{8}+5\times 3}{6}=3\text{ and }37+25-\left(11+19-4\right)=36$$

Add 18 and 6 to get 24.

$$\frac{\frac{24}{8}+5\times 3}{6}=3\text{ and }37+25-\left(11+19-4\right)=36$$

Divide 24 by 8 to get 3.

$$\frac{3+5\times 3}{6}=3\text{ and }37+25-\left(11+19-4\right)=36$$

Multiply 5 and 3 to get 15.

$$\frac{3+15}{6}=3\text{ and }37+25-\left(11+19-4\right)=36$$

Add 3 and 15 to get 18.

$$\frac{18}{6}=3\text{ and }37+25-\left(11+19-4\right)=36$$

Divide 18 by 6 to get 3.

$$3=3\text{ and }37+25-\left(11+19-4\right)=36$$

Compare 3 and 3.

$$\text{true}\text{ and }37+25-\left(11+19-4\right)=36$$

Add 11 and 19 to get 30.

$$\text{true}\text{ and }37+25-\left(30-4\right)=36$$

Subtract 4 from 30 to get 26.

$$\text{true}\text{ and }37+25-26=36$$

Subtract 26 from 25 to get -1.

$$\text{true}\text{ and }37-1=36$$

Subtract 1 from 37 to get 36.

$$\text{true}\text{ and }36=36$$

Compare 36 and 36.

$$\text{true}\text{ and }\text{true}$$

The conjunction of \text{true} and \text{true} is \text{true}.

$$\text{true}$$