Solve {l}{[(-147+39)div6+14]}{(-2)^3*(-3)^2}

$$\left. \begin{array} { l } { [ ( - 147 + 39 ) \div 6 + 14 ] } \\ { ( - 2 ) ^ { 3 } \times ( - 3 ) ^ { 2 } } \end{array} \right.$$

Sort

$$-72,-4$$

Solution Steps

Add -147 and 39 to get -108.

$$sort(\frac{-108}{6}+14,\left(-2\right)^{3}\left(-3\right)^{2})$$

Divide -108 by 6 to get -18.

$$sort(-18+14,\left(-2\right)^{3}\left(-3\right)^{2})$$

Add -18 and 14 to get -4.

$$sort(-4,\left(-2\right)^{3}\left(-3\right)^{2})$$

Calculate -2 to the power of 3 and get -8.

$$sort(-4,-8\left(-3\right)^{2})$$

Calculate -3 to the power of 2 and get 9.

$$sort(-4,-8\times 9)$$

Multiply -8 and 9 to get -72.

$$sort(-4,-72)$$

To sort the list, start from a single element -4.

$$-4$$

Insert -72 to the appropriate location in the new list.

$$-72,-4$$

Evaluate

$$-4,\ -72$$