Solve for z, y
y = \frac{400}{3} = 133\frac{1}{3} \approx 133.333333333
z = \frac{650}{3} = 216\frac{2}{3} \approx 216.666666667
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z=\frac{650}{3}
Consider the first equation. Divide both sides by 3.
y+\frac{650}{3}=350
Consider the second equation. Insert the known values of variables into the equation.
y=350-\frac{650}{3}
Subtract \frac{650}{3} from both sides.
y=\frac{400}{3}
Subtract \frac{650}{3} from 350 to get \frac{400}{3}.
z=\frac{650}{3} y=\frac{400}{3}
The system is now solved.
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