Solve {l}{z+{(-15)}=-21}{a=z}{b=a}{c=b}{text{Solvefor}dtext{where}}{d=c}

$$\left. \begin{array} { l } { z + {(-15)} = -21 }\\ { a = z }\\ { b = a }\\ { c = b }\\ { \text{Solve for } d \text{ where} } \\ { d = c } \end{array} \right.$$

Solve for z, a, b, c, d

$$d=-6$$

Solution Steps

Consider the first equation. Add 15 to both sides.

$$z=-21+15$$

Add -21 and 15 to get -6.

$$z=-6$$

Consider the second equation. Insert the known values of variables into the equation.

$$a=-6$$

Consider the third equation. Insert the known values of variables into the equation.

$$b=-6$$

Consider the fourth equation. Insert the known values of variables into the equation.

$$c=-6$$

Consider the fifth equation. Insert the known values of variables into the equation.

$$d=-6$$

The system is now solved.

$$z=-6 a=-6 b=-6 c=-6 d=-6$$