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Solve for x, y, z
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z=4x+2\times 5x
Substitute 5x for y in the equation z=4x+2y.
x=\frac{1}{14}z z=a
Solve the second equation for x and the third equation for z.
x=\frac{1}{14}a
Substitute a for z in the equation x=\frac{1}{14}z.
y=5\times \frac{1}{14}a
Substitute \frac{1}{14}a for x in the equation y=5x.
y=\frac{5}{14}a
Calculate y from y=5\times \frac{1}{14}a.
x=\frac{1}{14}a y=\frac{5}{14}a z=a
The system is now solved.