Solve {l}{y=10}{z=2}{a=y-{(z+z^2)}}{text{Solvefor}btext{where}}{b=a}

$$\left. \begin{array} { l } { y = 10 }\\ { z = 2 }\\ { a = y - {(z + z ^ {2})} }\\ { \text{Solve for } b \text{ where} } \\ { b = a } \end{array} \right.$$

Solve for y, z, a, b

$$b=4$$

Solution Steps

Consider the third equation. Insert the known values of variables into the equation.

$$a=10-\left(2+2^{2}\right)$$

Calculate 2 to the power of 2 and get 4.

$$a=10-\left(2+4\right)$$

Add 2 and 4 to get 6.

$$a=10-6$$

Subtract 6 from 10 to get 4.

$$a=4$$

Consider the fourth equation. Insert the known values of variables into the equation.

$$b=4$$

The system is now solved.

$$y=10 z=2 a=4 b=4$$