Solve {l}{y+9=1}{z=y}{a=z}{b=a}{c=b}{text{Solvefor}dtext{where}}{d=c}

$$\left. \begin{array} { l } { y + 9 = 1 }\\ { z = y }\\ { a = z }\\ { b = a }\\ { c = b }\\ { \text{Solve for } d \text{ where} } \\ { d = c } \end{array} \right.$$

Solve for y, z, a, b, c, d

$$d=-8$$

Solution Steps

Consider the first equation. Subtract 9 from both sides.

$$y=1-9$$

Subtract 9 from 1 to get -8.

$$y=-8$$

Consider the second equation. Insert the known values of variables into the equation.

$$z=-8$$

Consider the third equation. Insert the known values of variables into the equation.

$$a=-8$$

Consider the fourth equation. Insert the known values of variables into the equation.

$$b=-8$$

Consider the fifth equation. Insert the known values of variables into the equation.

$$c=-8$$

Consider the equation (6). Insert the known values of variables into the equation.

$$d=-8$$

The system is now solved.

$$y=-8 z=-8 a=-8 b=-8 c=-8 d=-8$$