Solve for y, z, a
a=3
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4y+6-4=14
Consider the first equation. Combine y and 3y to get 4y.
4y+2=14
Subtract 4 from 6 to get 2.
4y=14-2
Subtract 2 from both sides.
4y=12
Subtract 2 from 14 to get 12.
y=\frac{12}{4}
Divide both sides by 4.
y=3
Divide 12 by 4 to get 3.
y=3 z=3 a=3
The system is now solved.
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