Solve {l}{y+3=x}{x=3}{z=y}{a=z}{b=a}{c=b}{text{Solvefor}dtext{where}}{d=c}

$$\left. \begin{array} { l } { y + 3 = x }\\ { x = 3 }\\ { z = y }\\ { a = z }\\ { b = a }\\ { c = b }\\ { \text{Solve for } d \text{ where} } \\ { d = c } \end{array} \right.$$

Solve for y, x, z, a, b, c, d

$$d=0$$

Solution Steps

Consider the first equation. Insert the known values of variables into the equation.

$$y+3=3$$

Subtract 3 from both sides.

$$y=3-3$$

Subtract 3 from 3 to get 0.

$$y=0$$

Consider the third equation. Insert the known values of variables into the equation.

$$z=0$$

Consider the fourth equation. Insert the known values of variables into the equation.

$$a=0$$

Consider the fifth equation. Insert the known values of variables into the equation.

$$b=0$$

Consider the equation (6). Insert the known values of variables into the equation.

$$c=0$$

Consider the equation (7). Insert the known values of variables into the equation.

$$d=0$$

The system is now solved.

$$y=0 x=3 z=0 a=0 b=0 c=0 d=0$$