Solve {l}{x-{(x*30/100)}=63}{y=24}{text{Solvefor}ztext{where}}{z=y}

$$\left. \begin{array} { l } { x - {(x \cdot \frac{30}{100})} = 63 }\\ { y = 24 }\\ { \text{Solve for } z \text{ where} } \\ { z = y } \end{array} \right.$$

Solve for x, y, z

$$z=24$$

Solution Steps

Consider the first equation. Reduce the fraction \frac{30}{100} to lowest terms by extracting and canceling out 10.

$$x-x\times \frac{3}{10}=63$$

Combine x and -x\times \frac{3}{10} to get \frac{7}{10}x.

$$\frac{7}{10}x=63$$

Multiply both sides by \frac{10}{7}, the reciprocal of \frac{7}{10}.

$$x=63\times \frac{10}{7}$$

Multiply 63 and \frac{10}{7} to get 90.

$$x=90$$

The system is now solved.

$$x=90 y=24 z=24$$