Solve {l}{x{(.8)}=5+x}{y=5*{(0)}+x}{z=y}{a=z}{text{Solvefor}btext{where}}{b=a}

$$\left. \begin{array} { l } { x {(.8)} = 5 + x }\\ { y = 5 \cdot {(0)} + x }\\ { z = y }\\ { a = z }\\ { \text{Solve for } b \text{ where} } \\ { b = a } \end{array} \right.$$

Solve for x, y, z, a, b

$$b=-25$$

Solution Steps

Consider the first equation. Subtract x from both sides.

$$x\times 0.8-x=5$$

Combine x\times 0.8 and -x to get -0.2x.

$$-0.2x=5$$

Divide both sides by -0.2.

$$x=\frac{5}{-0.2}$$

Expand \frac{5}{-0.2} by multiplying both numerator and the denominator by 10.

$$x=\frac{50}{-2}$$

Divide 50 by -2 to get -25.

$$x=-25$$

Consider the second equation. Insert the known values of variables into the equation.

$$y=5\times 0-25$$

Multiply 5 and 0 to get 0.

$$y=0-25$$

Subtract 25 from 0 to get -25.

$$y=-25$$

Consider the third equation. Insert the known values of variables into the equation.

$$z=-25$$

Consider the fourth equation. Insert the known values of variables into the equation.

$$a=-25$$

Consider the fifth equation. Insert the known values of variables into the equation.

$$b=-25$$

The system is now solved.

$$x=-25 y=-25 z=-25 a=-25 b=-25$$