Solve {l}{x{(.8)}=5+x}{y=5*{(0)}+x}{text{Solvefor}ztext{where}}{z=y}

$$\left. \begin{array} { l } { x {(.8)} = 5 + x }\\ { y = 5 \cdot {(0)} + x }\\ { \text{Solve for } z \text{ where} } \\ { z = y } \end{array} \right.$$

Solve for x, y, z

$$z=-25$$

Solution Steps

Consider the first equation. Subtract x from both sides.

$$x\times 0.8-x=5$$

Combine x\times 0.8 and -x to get -0.2x.

$$-0.2x=5$$

Divide both sides by -0.2.

$$x=\frac{5}{-0.2}$$

Expand \frac{5}{-0.2} by multiplying both numerator and the denominator by 10.

$$x=\frac{50}{-2}$$

Divide 50 by -2 to get -25.

$$x=-25$$

Consider the second equation. Insert the known values of variables into the equation.

$$y=5\times 0-25$$

Multiply 5 and 0 to get 0.

$$y=0-25$$

Subtract 25 from 0 to get -25.

$$y=-25$$

Consider the third equation. Insert the known values of variables into the equation.

$$z=-25$$

The system is now solved.

$$x=-25 y=-25 z=-25$$