Solve for x, y, z
z=729
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y=9^{2}\times 9^{1}
Consider the second equation. Insert the known values of variables into the equation.
y=9^{3}
To multiply powers of the same base, add their exponents. Add 2 and 1 to get 3.
y=729
Calculate 9 to the power of 3 and get 729.
z=729
Consider the third equation. Insert the known values of variables into the equation.
x=9 y=729 z=729
The system is now solved.
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