Solve {l}{x=5}{y=2}{z=-2(x-y)^3}{a=z}{b=a}{text{Solvefor}ctext{where}}{c=b}

$$\left. \begin{array} { l } { x = 5 }\\ { y = 2 }\\ { z = -2 {(x - y)} ^ {3} }\\ { a = z }\\ { b = a }\\ { \text{Solve for } c \text{ where} } \\ { c = b } \end{array} \right.$$

Solve for x, y, z, a, b, c

$$c=-54$$

Solution Steps

Consider the third equation. Insert the known values of variables into the equation.

$$z=-2\left(5-2\right)^{3}$$

Subtract 2 from 5 to get 3.

$$z=-2\times 3^{3}$$

Calculate 3 to the power of 3 and get 27.

$$z=-2\times 27$$

Multiply -2 and 27 to get -54.

$$z=-54$$

Consider the fourth equation. Insert the known values of variables into the equation.

$$a=-54$$

Consider the fifth equation. Insert the known values of variables into the equation.

$$b=-54$$

Consider the equation (6). Insert the known values of variables into the equation.

$$c=-54$$

The system is now solved.

$$x=5 y=2 z=-54 a=-54 b=-54 c=-54$$