Solve {l}{x=4}{y=3}{z=sqrt{x^2+y^2}}{text{Solvefor}atext{where}}{a=z}

$$\left. \begin{array} { l } { x = 4 }\\ { y = 3 }\\ { z = \sqrt{x ^ {2} + y ^ {2}} }\\ { \text{Solve for } a \text{ where} } \\ { a = z } \end{array} \right.$$

Solve for x, y, z, a

$$a=5$$

Solution Steps

Consider the third equation. Insert the known values of variables into the equation.

$$z=\sqrt{4^{2}+3^{2}}$$

Calculate 4 to the power of 2 and get 16.

$$z=\sqrt{16+3^{2}}$$

Calculate 3 to the power of 2 and get 9.

$$z=\sqrt{16+9}$$

Add 16 and 9 to get 25.

$$z=\sqrt{25}$$

Calculate the square root of 25 and get 5.

$$z=5$$

Consider the fourth equation. Insert the known values of variables into the equation.

$$a=5$$

The system is now solved.

$$x=4 y=3 z=5 a=5$$