Solve {l}{x=4}{y={(x^2+x)}{(5x^2+6)}}{text{Solvefor}ztext{where}}{z=y}

$$\left. \begin{array} { l } { x = 4 }\\ { y = {(x ^ {2} + x)} {(5 x ^ {2} + 6)} }\\ { \text{Solve for } z \text{ where} } \\ { z = y } \end{array} \right.$$

Solve for x, y, z

$$z=1720$$

Solution Steps

Consider the second equation. Insert the known values of variables into the equation.

$$y=\left(4^{2}+4\right)\left(5\times 4^{2}+6\right)$$

Calculate 4 to the power of 2 and get 16.

$$y=\left(16+4\right)\left(5\times 4^{2}+6\right)$$

Add 16 and 4 to get 20.

$$y=20\left(5\times 4^{2}+6\right)$$

Calculate 4 to the power of 2 and get 16.

$$y=20\left(5\times 16+6\right)$$

Multiply 5 and 16 to get 80.

$$y=20\left(80+6\right)$$

Add 80 and 6 to get 86.

$$y=20\times 86$$

Multiply 20 and 86 to get 1720.

$$y=1720$$

Consider the third equation. Insert the known values of variables into the equation.

$$z=1720$$

The system is now solved.

$$x=4 y=1720 z=1720$$