Solve {l}{x=3}{y=2}{z={(2^2x^2/xy^2)}^2}{text{Solvefor}atext{where}}{a=z}

$$\left. \begin{array} { l } { x = 3 }\\ { y = 2 }\\ { z = {(\frac{2 ^ {2} x ^ {2}}{x y ^ {2}})} ^ {2} }\\ { \text{Solve for } a \text{ where} } \\ { a = z } \end{array} \right.$$

Solve for x, y, z, a

$$a=9$$

Solution Steps

Consider the third equation. Insert the known values of variables into the equation.

$$z=\left(\frac{2^{2}\times 3^{2}}{3\times 2^{2}}\right)^{2}$$

Cancel out 3\times 2^{2} in both numerator and denominator.

$$z=3^{2}$$

Calculate 3 to the power of 2 and get 9.

$$z=9$$

Consider the fourth equation. Insert the known values of variables into the equation.

$$a=9$$

The system is now solved.

$$x=3 y=2 z=9 a=9$$