Solve {l}{x=3}{y=18x^-3}{z=y}{text{Solvefor}atext{where}}{a=z}

$$\left. \begin{array} { l } { x = 3 }\\ { y = 18 x ^ {-3} }\\ { z = y }\\ { \text{Solve for } a \text{ where} } \\ { a = z } \end{array} \right.$$

Solve for x, y, z, a

$$a=\frac{2}{3}\approx 0.666666667$$

Solution Steps

Consider the second equation. Insert the known values of variables into the equation.

$$y=18\times 3^{-3}$$

Calculate 3 to the power of -3 and get \frac{1}{27}.

$$y=18\times \frac{1}{27}$$

Multiply 18 and \frac{1}{27} to get \frac{2}{3}.

$$y=\frac{2}{3}$$

Consider the third equation. Insert the known values of variables into the equation.

$$z=\frac{2}{3}$$

Consider the fourth equation. Insert the known values of variables into the equation.

$$a=\frac{2}{3}$$

The system is now solved.

$$x=3 y=\frac{2}{3} z=\frac{2}{3} a=\frac{2}{3}$$