Solve {l}{x=3}{y=-2}{z=x+y{(5+x^2)}}{text{Solvefor}atext{where}}{a=z}

$$\left. \begin{array} { l } { x = 3 }\\ { y = -2 }\\ { z = x + y {(5 + x ^ {2})} }\\ { \text{Solve for } a \text{ where} } \\ { a = z } \end{array} \right.$$

Solve for x, y, z, a

$$a=-25$$

Solution Steps

Consider the third equation. Insert the known values of variables into the equation.

$$z=3-2\left(5+3^{2}\right)$$

Calculate 3 to the power of 2 and get 9.

$$z=3-2\left(5+9\right)$$

Add 5 and 9 to get 14.

$$z=3-2\times 14$$

Multiply -2 and 14 to get -28.

$$z=3-28$$

Subtract 28 from 3 to get -25.

$$z=-25$$

Consider the fourth equation. Insert the known values of variables into the equation.

$$a=-25$$

The system is now solved.

$$x=3 y=-2 z=-25 a=-25$$