Solve {l}{x=2y+2}{y=3z/4}{z=5}{a=73}{text{Solvefor}btext{where}}{b=a}

$$\left. \begin{array} { l } { x = 2 y + 2 }\\ { y = \frac{3 z}{4} }\\ { z = 5 }\\ { a = 73 }\\ { \text{Solve for } b \text{ where} } \\ { b = a } \end{array} \right.$$

Solve for x, y, z, a, b

$$b=73$$

Solution Steps

Consider the second equation. Insert the known values of variables into the equation.

$$y=\frac{3\times 5}{4}$$

Multiply 3 and 5 to get 15.

$$y=\frac{15}{4}$$

Consider the first equation. Insert the known values of variables into the equation.

$$x=2\times \frac{15}{4}+2$$

Multiply 2 and \frac{15}{4} to get \frac{15}{2}.

$$x=\frac{15}{2}+2$$

Add \frac{15}{2} and 2 to get \frac{19}{2}.

$$x=\frac{19}{2}$$

The system is now solved.

$$x=\frac{19}{2} y=\frac{15}{4} z=5 a=73 b=73$$